(2/3)p-25=115

Solution for (2/3)p-25=115 equation:

(2/3)p-25=115

We move all terms to the left:

(2/3)p-25-(115)=0


Domain of the equation: 3)p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(+2/3)p-25-115=0

We add all the numbers together, and all the variables

(+2/3)p-140=0

We multiply parentheses

2p^2-140=0

a = 2; b = 0; c = -140;
Δ = b2-4ac
Δ = 02-4·2·(-140)
Δ = 1120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1120}=\sqrt{16*70}=\sqrt{16}*\sqrt{70}=4\sqrt{70}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{70}}{2*2}=\frac{0-4\sqrt{70}}{4}
=-\frac{4\sqrt{70}}{4}
=-\sqrt{70}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{70}}{2*2}=\frac{0+4\sqrt{70}}{4}
=\frac{4\sqrt{70}}{4}
=\sqrt{70}
$