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(2/3)t-(1/6)t=t-(9/2)
We move all terms to the left:
(2/3)t-(1/6)t-(t-(9/2))=0
Domain of the equation: 3)t!=0
t!=0/1
t!=0
t∈R
Domain of the equation: 6)t!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
(+2/3)t-(+1/6)t-(t-(+9/2))=0
We multiply parentheses
2t^2-t^2-(t-(+9/2))=0
We multiply all the terms by the denominator
2t^2*2))-t^2*2))-(t-(+9=0
Wy multiply elements
8t^4=0
We do not support etpression: t^4
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