(2/3)x+(1/2)(x-4)=x-4

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Solution for (2/3)x+(1/2)(x-4)=x-4 equation: 



(2/3)x+(1/2)(x-4)=x-4

We move all terms to the left:

(2/3)x+(1/2)(x-4)-(x-4)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)(x-4)!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x+(+1/2)(x-4)-(x-4)=0

We multiply parentheses

2x^2+(+1/2)(x-4)-(x-4)=0

We get rid of parentheses

2x^2+(+1/2)(x-4)-x+4=0

We multiply parentheses ..

2x^2+(+x^2+1/2*-4)-x+4=0

We multiply all the terms by the denominator


x^2+2x^2*2*-x*2*+1-4)+(-4)+4*2*-4)=0

We add all the numbers together, and all the variables

x^2+2x^2*2*-x*2*=0

Wy multiply elements

x^2+4x^3-2x^2=0

We do not support expression: x^3

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