(2/3)x+(1/3)=-(7/3)

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Solution for (2/3)x+(1/3)=-(7/3) equation: 



(2/3)x+(1/3)=-(7/3)

We move all terms to the left:

(2/3)x+(1/3)-(-(7/3))=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x+(+1/3)-(-(+7/3))=0

We multiply parentheses

2x^2+(+1/3)-(-(+7/3))=0

We get rid of parentheses

2x^2+1/3-(-(+7/3))=0

We calculate fractions


2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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