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(2/3)x+(5/2)=-(1/2)
We move all terms to the left:
(2/3)x+(5/2)-(-(1/2))=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x+(+5/2)-(-(+1/2))=0
We multiply parentheses
2x^2+(+5/2)-(-(+1/2))=0
We get rid of parentheses
2x^2+5/2-(-(+1/2))=0
We calculate fractions
2x^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{4}=0$
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