(2/3)x+10=-(1/3x)+12

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Solution for (2/3)x+10=-(1/3x)+12 equation: 



(2/3)x+10=-(1/3x)+12

We move all terms to the left:

(2/3)x+10-(-(1/3x)+12)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3x)+12)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x-(-(+1/3x)+12)+10=0

We multiply parentheses

2x^2-(-(+1/3x)+12)+10=0

We multiply all the terms by the denominator


2x^2*3x)+12)-(-(+10*3x)+12)+1=0

Wy multiply elements

6x^3+30x=0

We do not support expression: x^3

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