(2/3)x+1=-(1/3)x-1

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Solution for (2/3)x+1=-(1/3)x-1 equation:



(2/3)x+1=-(1/3)x-1
We move all terms to the left:
(2/3)x+1-(-(1/3)x-1)=0
Domain of the equation: 3)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3)x-1)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+2/3)x-(-(+1/3)x-1)+1=0
We multiply parentheses
2x^2-(-(+1/3)x-1)+1=0
We multiply all the terms by the denominator
2x^2*3)x-1)-(-(+1*3)x-1)+1=0
We add all the numbers together, and all the variables
2x^2*3)x-1)-(-3x-1)+1=0
Wy multiply elements
6x^3=0
We do not support expression: x^3

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