(2/3)x+1=x-4

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Solution for (2/3)x+1=x-4 equation: 



(2/3)x+1=x-4

We move all terms to the left:

(2/3)x+1-(x-4)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x-(x-4)+1=0

We multiply parentheses

2x^2-(x-4)+1=0

We get rid of parentheses

2x^2-x+4+1=0

We add all the numbers together, and all the variables

2x^2-1x+5=0

a = 2; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·2·5
Δ = -39
Delta is less than zero, so there is no solution for the equation

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