(2/3)x+2=26/10

Solution for (2/3)x+2=26/10 equation:

(2/3)x+2=26/10

We move all terms to the left:

(2/3)x+2-(26/10)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x+2-(+26/10)=0

We multiply parentheses

2x^2+2-(+26/10)=0

We get rid of parentheses

2x^2+2-26/10=0

We multiply all the terms by the denominator


2x^2*10-26+2*10=0

We add all the numbers together, and all the variables

2x^2*10-6=0

Wy multiply elements

20x^2-6=0

a = 20; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·20·(-6)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*20}=\frac{0-4\sqrt{30}}{40}
=-\frac{4\sqrt{30}}{40}
=-\frac{\sqrt{30}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*20}=\frac{0+4\sqrt{30}}{40}
=\frac{4\sqrt{30}}{40}
=\frac{\sqrt{30}}{10}
$