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(2/3)x+3+2x+1=180
We move all terms to the left:
(2/3)x+3+2x+1-(180)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x+2x+3+1-180=0
We add all the numbers together, and all the variables
2x+(+2/3)x-176=0
We multiply parentheses
2x^2+2x-176=0
a = 2; b = 2; c = -176;
Δ = b2-4ac
Δ = 22-4·2·(-176)
Δ = 1412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1412}=\sqrt{4*353}=\sqrt{4}*\sqrt{353}=2\sqrt{353}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{353}}{2*2}=\frac{-2-2\sqrt{353}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{353}}{2*2}=\frac{-2+2\sqrt{353}}{4} $
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