(2/3)x+4=(1/6)-5

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Solution for (2/3)x+4=(1/6)-5 equation: 



(2/3)x+4=(1/6)-5

We move all terms to the left:

(2/3)x+4-((1/6)-5)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x+4-((+1/6)-5)=0

We multiply parentheses

2x^2+4-((+1/6)-5)=0

We multiply all the terms by the denominator


2x^2*6)-5)+4*6)-5)-((+1=0

Wy multiply elements

72x^4=0

We do not support expression: x^4

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