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(2/3)x+4=(3/5)x+-2
We move all terms to the left:
(2/3)x+4-((3/5)x+-2)=0
Domain of the equation: 3)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5)x+-2)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x-((+3/5)x+-2)+4=0
We use the square of the difference formula
(+2/3)x-((+3/5)x-2)+4=0
We multiply parentheses
2x^2-((+3/5)x-2)+4=0
We multiply all the terms by the denominator
2x^2*5)x-2)-((+4*5)x-2)+3=0
We add all the numbers together, and all the variables
2x^2*5)x-2)-(20x-2)+3=0
Wy multiply elements
10x^3=0
We do not support expression: x^3
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