(2/3)x+4=6x-10

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Solution for (2/3)x+4=6x-10 equation: 



(2/3)x+4=6x-10

We move all terms to the left:

(2/3)x+4-(6x-10)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x-(6x-10)+4=0

We multiply parentheses

2x^2-(6x-10)+4=0

We get rid of parentheses

2x^2-6x+10+4=0

We add all the numbers together, and all the variables

2x^2-6x+14=0

a = 2; b = -6; c = +14;
Δ = b2-4ac
Δ = -62-4·2·14
Δ = -76
Delta is less than zero, so there is no solution for the equation

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