(2/3)x+x=300

Solution for (2/3)x+x=300 equation:

(2/3)x+x=300

We move all terms to the left:

(2/3)x+x-(300)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x+x-300=0

We add all the numbers together, and all the variables

x+(+2/3)x-300=0

We multiply parentheses

2x^2+x-300=0

a = 2; b = 1; c = -300;
Δ = b2-4ac
Δ = 12-4·2·(-300)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-49}{2*2}=\frac{-50}{4}
=-12+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+49}{2*2}=\frac{48}{4}
=12
$