(2/3)x-(1/6)=(x/9)

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Solution for (2/3)x-(1/6)=(x/9) equation: 



(2/3)x-(1/6)=(x/9)

We move all terms to the left:

(2/3)x-(1/6)-((x/9))=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x-((+x/9))-(+1/6)=0

We multiply parentheses

2x^2-((+x/9))-(+1/6)=0

We get rid of parentheses

2x^2-((+x/9))-1/6=0

We calculate fractions


2x^2+(-((+x*6)/()+()/()=0



We calculate terms in parentheses: +(-((+x*6)/()+()/(), so:

-((+x*6)/()+()/(

We can not solve this equation

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