(2/3)x-7=(3/4)x+2

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Solution for (2/3)x-7=(3/4)x+2 equation:



(2/3)x-7=(3/4)x+2
We move all terms to the left:
(2/3)x-7-((3/4)x+2)=0
Domain of the equation: 3)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 4)x+2)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+2/3)x-((+3/4)x+2)-7=0
We multiply parentheses
2x^2-((+3/4)x+2)-7=0
We multiply all the terms by the denominator
2x^2*4)x+2)-((-7*4)x+2)+3=0
We add all the numbers together, and all the variables
2x^2*4)x+2)-((-28)x+2)+3=0
Wy multiply elements
8x^3-28)x+2)+3=0
We do not support expression: x^3

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