(2/3)x=7040

Solution for (2/3)x=7040 equation:

(2/3)x=7040

We move all terms to the left:

(2/3)x-(7040)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x-7040=0

We multiply parentheses

2x^2-7040=0

a = 2; b = 0; c = -7040;
Δ = b2-4ac
Δ = 02-4·2·(-7040)
Δ = 56320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56320}=\sqrt{1024*55}=\sqrt{1024}*\sqrt{55}=32\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{55}}{2*2}=\frac{0-32\sqrt{55}}{4}
=-\frac{32\sqrt{55}}{4}
=-8\sqrt{55}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{55}}{2*2}=\frac{0+32\sqrt{55}}{4}
=\frac{32\sqrt{55}}{4}
=8\sqrt{55}
$