(2/3)y=42

Solution for (2/3)y=42 equation:

(2/3)y=42

We move all terms to the left:

(2/3)y-(42)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+2/3)y-42=0

We multiply parentheses

2y^2-42=0

a = 2; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·2·(-42)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{21}}{2*2}=\frac{0-4\sqrt{21}}{4}
=-\frac{4\sqrt{21}}{4}
=-\sqrt{21}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{21}}{2*2}=\frac{0+4\sqrt{21}}{4}
=\frac{4\sqrt{21}}{4}
=\sqrt{21}
$