(2/3)y=y-62

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Solution for (2/3)y=y-62 equation: 



(2/3)y=y-62

We move all terms to the left:

(2/3)y-(y-62)=0



Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+2/3)y-(y-62)=0

We multiply parentheses

2y^2-(y-62)=0

We get rid of parentheses

2y^2-y+62=0

We add all the numbers together, and all the variables

2y^2-1y+62=0

a = 2; b = -1; c = +62;
Δ = b2-4ac
Δ = -12-4·2·62
Δ = -495
Delta is less than zero, so there is no solution for the equation

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