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(2/3+5x)=(5/6-6x)
We move all terms to the left:
(2/3+5x)-((5/6-6x))=0
Domain of the equation: 3+5x)!=0
We move all terms containing x to the left, all other terms to the right
5x)!=-3
x!=-3/1
x!=-3
x∈R
Domain of the equation: 6-6x))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-6x))!=-6
x!=-6/1
x!=-6
x∈R
(+5x+2/3)-((-6x+5/6))=0
We get rid of parentheses
5x-((-6x+5/6))+2/3=0
We calculate fractions
5x+(-((-6x+5*3)/()+()/()=0
We calculate terms in parentheses: +(-((-6x+5*3)/()+()/(), so:
-((-6x+5*3)/()+()/(
We can not solve this equation
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