(2/3+x)=5

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Solution for (2/3+x)=5 equation:



(2/3+x)=5
We move all terms to the left:
(2/3+x)-(5)=0
Domain of the equation: 3+x)!=0
We move all terms containing x to the left, all other terms to the right
x)!=-3
x!=-3/1
x!=-3
x∈R
We add all the numbers together, and all the variables
(+x+2/3)-5=0
We get rid of parentheses
x-5+2/3=0
We multiply all the terms by the denominator
x*3+2-5*3=0
We add all the numbers together, and all the variables
x*3-13=0
Wy multiply elements
3x-13=0
We move all terms containing x to the left, all other terms to the right
3x=13
x=13/3
x=4+1/3

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