(2/3g)+1=19

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Solution for (2/3g)+1=19 equation: 



(2/3g)+1=19

We move all terms to the left:

(2/3g)+1-(19)=0



Domain of the equation: 3g)!=0

g!=0/1

g!=0

g∈R



We add all the numbers together, and all the variables

(+2/3g)+1-19=0

We add all the numbers together, and all the variables

(+2/3g)-18=0

We get rid of parentheses

2/3g-18=0

We multiply all the terms by the denominator


-18*3g+2=0

Wy multiply elements

-54g+2=0

We move all terms containing g to the left, all other terms to the right

-54g=-2

g=-2/-54

g=1/27

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