(2/3x)+(1/x)=30

Solution for (2/3x)+(1/x)=30 equation:

(2/3x)+(1/x)=30

We move all terms to the left:

(2/3x)+(1/x)-(30)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3x)+(+1/x)-30=0

We get rid of parentheses

2/3x+1/x-30=0

We calculate fractions


2x/3x^2+3x/3x^2-30=0

We multiply all the terms by the denominator


2x+3x-30*3x^2=0

We add all the numbers together, and all the variables

5x-30*3x^2=0

Wy multiply elements

-90x^2+5x=0

a = -90; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-90)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-90}=\frac{-10}{-180}
=1/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-90}=\frac{0}{-180}
=0
$