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(2/3x)+10=(36+x)/5
We move all terms to the left:
(2/3x)+10-((36+x)/5)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3x)-((x+36)/5)+10=0
We get rid of parentheses
2/3x-((x+36)/5)+10=0
We calculate fractions
()/15x^2+(-((x+36)*3x)/15x^2+10=0
We calculate fractions
We do not support expression: x^4
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