(2/3x)+1=(2/3x)-1

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Solution for (2/3x)+1=(2/3x)-1 equation: 


x in (-oo:+oo)

(2/3)*x+1 = (2/3)*x-1 // - (2/3)*x-1

(2/3)*x-((2/3)*x)+1+1 = 0

(2/3)*x+(-2/3)*x+1+1 = 0

2 = 0

x belongs to the empty set

x belongs to the empty set

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