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(2/3x)+4=(1/6x)-5
We move all terms to the left:
(2/3x)+4-((1/6x)-5)=0
Domain of the equation: 3x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 6x)-5)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3x)-((+1/6x)-5)+4=0
We get rid of parentheses
2/3x-((+1/6x)-5)+4=0
We calculate fractions
12x/18x^2+(-((+1*3x)/18x^2+4=0
We calculate fractions
We do not support expression: x^4
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