(2/3x)+5=26

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Solution for (2/3x)+5=26 equation: 



(2/3x)+5=26

We move all terms to the left:

(2/3x)+5-(26)=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3x)+5-26=0

We add all the numbers together, and all the variables

(+2/3x)-21=0

We get rid of parentheses

2/3x-21=0

We multiply all the terms by the denominator


-21*3x+2=0

Wy multiply elements

-63x+2=0

We move all terms containing x to the left, all other terms to the right

-63x=-2

x=-2/-63

x=2/63

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