(2/3x)-(1/3)-3=(-20/9)

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Solution for (2/3x)-(1/3)-3=(-20/9) equation: 



(2/3x)-(1/3)-3=(-20/9)

We move all terms to the left:

(2/3x)-(1/3)-3-((-20/9))=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3x)-3-(+1/3)-((-20/9))=0

We get rid of parentheses

2/3x-3-1/3-((-20/9))=0

We calculate fractions


()/729x^2+()/729x^2+(-((-20*3x*3)/729x^2-3=0

We calculate fractions

We do not support expression: x^4

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