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(2/3x)-(1/5x)=x-1
We move all terms to the left:
(2/3x)-(1/5x)-(x-1)=0
Domain of the equation: 3x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3x)-(+1/5x)-(x-1)=0
We get rid of parentheses
2/3x-1/5x-x+1=0
We calculate fractions
-x+10x/15x^2+(-3x)/15x^2+1=0
We add all the numbers together, and all the variables
-1x+10x/15x^2+(-3x)/15x^2+1=0
We multiply all the terms by the denominator
-1x*15x^2+10x+(-3x)+1*15x^2=0
We add all the numbers together, and all the variables
10x-1x*15x^2+(-3x)+1*15x^2=0
Wy multiply elements
-15x^3+15x^2+10x+(-3x)=0
We get rid of parentheses
-15x^3+15x^2+10x-3x=0
We do not support expression: x^3
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