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(2/3x)-6=3+(1/2x)
We move all terms to the left:
(2/3x)-6-(3+(1/2x))=0
Domain of the equation: 3x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3x)-(3+(+1/2x))-6=0
We get rid of parentheses
2/3x-(3+(+1/2x))-6=0
We calculate fractions
4x/6x^2+(-(3+(+1*3x)/6x^2-6=0
We calculate fractions
We do not support expression: x^4
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