(2/3x+10)2+(1/3x+5)2)=90

Solution for (2/3x+10)2+(1/3x+5)2)=90 equation:

(2/3x+10)2+(1/3x+5)2)=90

We move all terms to the left:

(2/3x+10)2+(1/3x+5)2)-(90)=0


Domain of the equation: 3x+10)2!=0

x∈R



Domain of the equation: 3x+5)2)-90!=0

x∈R


We multiply parentheses

4x+(1/3x+5)2)-90+20=0

We multiply all the terms by the denominator


4x*3x+5)2)-90+20+(1=0

We add all the numbers together, and all the variables

4x*3x=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$