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(2/3x+1=5-8)
We move all terms to the left:
(2/3x+1-(5-8))=0
Domain of the equation: 3x+1-(5-8))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3x-(5-8))!=-1
x∈R
(2/3x+1-(-3))=0
We multiply all the terms by the denominator
(2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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