(2/3x+5)+(2/3x+2)=(7/3x+4)

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Solution for (2/3x+5)+(2/3x+2)=(7/3x+4) equation: 



(2/3x+5)+(2/3x+2)=(7/3x+4)

We move all terms to the left:

(2/3x+5)+(2/3x+2)-((7/3x+4))=0



Domain of the equation: 3x+5)!=0

x∈R





Domain of the equation: 3x+2)!=0

x∈R





Domain of the equation: 3x+4))!=0

x∈R



We get rid of parentheses

2/3x+2/3x-((7/3x+4))+5+2=0

We calculate fractions


6x/9x^2+(-((7*3x)/9x^2+5+2=0

We add all the numbers together, and all the variables

6x/9x^2+(-((+7*3x)/9x^2+5+2=0

We calculate fractions

We do not support expression: x^4

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