(2/3y)+2=(1/5)+y

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Solution for (2/3y)+2=(1/5)+y equation: 


y in (-oo:+oo)

(2/3)*y+2 = y+1/5 // - y+1/5

(2/3)*y-y-(1/5)+2 = 0

(2/3)*y-y-1/5+2 = 0

9/5-1/3*y = 0 // - 9/5

-1/3*y = -9/5 // : -1/3

y = -9/5/(-1/3)

y = 27/5

y = 27/5

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