(2/3y)+y=1

Solution for (2/3y)+y=1 equation:

(2/3y)+y=1

We move all terms to the left:

(2/3y)+y-(1)=0


Domain of the equation: 3y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+2/3y)+y-1=0

We add all the numbers together, and all the variables

y+(+2/3y)-1=0

We get rid of parentheses

y+2/3y-1=0

We multiply all the terms by the denominator


y*3y-1*3y+2=0

Wy multiply elements

3y^2-3y+2=0

a = 3; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·3·2
Δ = -15
Delta is less than zero, so there is no solution for the equation