(2/3z)=-6

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Solution for (2/3z)=-6 equation:



(2/3z)=-6
We move all terms to the left:
(2/3z)-(-6)=0
Domain of the equation: 3z)!=0
z!=0/1
z!=0
z∈R
We add all the numbers together, and all the variables
(+2/3z)-(-6)=0
We add all the numbers together, and all the variables
(+2/3z)+6=0
We get rid of parentheses
2/3z+6=0
We multiply all the terms by the denominator
6*3z+2=0
Wy multiply elements
18z+2=0
We move all terms containing z to the left, all other terms to the right
18z=-2
z=-2/18
z=-1/9

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