(2/4x-4)(x-5)=0

Solution for (2/4x-4)(x-5)=0 equation:

(2/4x-4)(x-5)=0


Domain of the equation: 4x-4)(x-5)!=0

x∈R


We multiply parentheses ..

(+2x^2-10x-4x+20)=0

We get rid of parentheses

2x^2-10x-4x+20=0

We add all the numbers together, and all the variables

2x^2-14x+20=0

a = 2; b = -14; c = +20;
Δ = b2-4ac
Δ = -142-4·2·20
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-6}{2*2}=\frac{8}{4}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+6}{2*2}=\frac{20}{4}
=5
$