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(2/5)(20x+40)=(2/3)(6x+6)
We move all terms to the left:
(2/5)(20x+40)-((2/3)(6x+6))=0
Domain of the equation: 5)(20x+40)!=0
x∈R
Domain of the equation: 3)(6x+6))!=0We add all the numbers together, and all the variables
x∈R
(+2/5)(20x+40)-((+2/3)(6x+6))=0
We multiply parentheses ..
(+40x^2+2/5*40)-((+2/3)(6x+6))=0
We calculate fractions
((+40x^2+2*3)(6x+6)))/600x^2+()/600x^2=0
We can not solve this equation
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