(2/5)(c)+4-(1/5)(c)=-9

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Solution for (2/5)(c)+4-(1/5)(c)=-9 equation: 



(2/5)(c)+4-(1/5)(c)=-9

We move all terms to the left:

(2/5)(c)+4-(1/5)(c)-(-9)=0



Domain of the equation: 5)c!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

(+2/5)c-(+1/5)c+4-(-9)=0

We add all the numbers together, and all the variables

(+2/5)c-(+1/5)c+13=0

We multiply parentheses

2c^2-c^2+13=0

We add all the numbers together, and all the variables

c^2+13=0

a = 1; b = 0; c = +13;
Δ = b2-4ac
Δ = 02-4·1·13
Δ = -52
Delta is less than zero, so there is no solution for the equation

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