(2/5)(x-23.50)=13.80

Solution for (2/5)(x-23.50)=13.80 equation:

(2/5)(x-23.50)=13.80

We move all terms to the left:

(2/5)(x-23.50)-(13.80)=0


Domain of the equation: 5)(x-23.50)!=0

x∈R


We add all the numbers together, and all the variables

(+2/5)(x-23.5)-(13.8)=0

We add all the numbers together, and all the variables

(+2/5)(x-23.5)-13.8=0

We multiply parentheses ..

(+2x^2+2/5*-23.5)-13.8=0

We multiply all the terms by the denominator


(+2x^2+2-(13.8)*5*-23.5)=0


We calculate terms in parentheses: +(+2x^2+2-(13.8)*5*-23.5), so:

+2x^2+2-(13.8)*5*-23.5

determiningTheFunctionDomain
2x^2+2-23.5-(13.8)*5*

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)


a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$