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(2/5)(x-3)-2=6
We move all terms to the left:
(2/5)(x-3)-2-(6)=0
Domain of the equation: 5)(x-3)!=0We add all the numbers together, and all the variables
x∈R
(+2/5)(x-3)-2-6=0
We add all the numbers together, and all the variables
(+2/5)(x-3)-8=0
We multiply parentheses ..
(+2x^2+2/5*-3)-8=0
We multiply all the terms by the denominator
(+2x^2+2-8*5*-3)=0
We get rid of parentheses
2x^2+2-3-8*5*=0
We add all the numbers together, and all the variables
2x^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{4}=0$
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