(2/5)(y-1)=(1/5)(y-7)

Solution for (2/5)(y-1)=(1/5)(y-7) equation:

(2/5)(y-1)=(1/5)(y-7)

We move all terms to the left:

(2/5)(y-1)-((1/5)(y-7))=0


Domain of the equation: 5)(y-1)!=0

y∈R



Domain of the equation: 5)(y-7))!=0

y∈R


We add all the numbers together, and all the variables

(+2/5)(y-1)-((+1/5)(y-7))=0

We multiply parentheses ..

(+2y^2+2/5*-1)-((+1/5)(y-7))=0

We calculate fractions


((+2y^2+2*5)(y-7)))/(-1)*5)(y-7))+5*)+()/(-1)*5)(y-7))+5*)=0

We calculate fractions


(((+2y^2+2*5)(y-7)))*(-1)*5)(y-7))+5*))/((*(-1)*5)y)+(-1)*5)(y-7))+5*)+()*()/((*(-1)*5)y)=0

We can not solve this equation