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(2/5)*h-7=(12/5)h-2h+3
We move all terms to the left:
(2/5)*h-7-((12/5)h-2h+3)=0
Domain of the equation: 5)*h!=0
h!=0/1
h!=0
h∈R
Domain of the equation: 5)h-2h+3)!=0We add all the numbers together, and all the variables
h!=0/1
h!=0
h∈R
(+2/5)*h-((+12/5)h-2h+3)-7=0
We multiply parentheses
2h^2-((+12/5)h-2h+3)-7=0
We multiply all the terms by the denominator
2h^2*5)h-2h+3)-((-7*5)h-2h+3)+12=0
We add all the numbers together, and all the variables
2h^2*5)h-2h+3)-((-35)h-2h+3)+12=0
Wy multiply elements
10h^3-35)h-2h+3)+12=0
We do not support ehpression: h^3
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