If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2/5)*x=26
We move all terms to the left:
(2/5)*x-(26)=0
Domain of the equation: 5)*x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5)*x-26=0
We multiply parentheses
2x^2-26=0
a = 2; b = 0; c = -26;
Δ = b2-4ac
Δ = 02-4·2·(-26)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{13}}{2*2}=\frac{0-4\sqrt{13}}{4} =-\frac{4\sqrt{13}}{4} =-\sqrt{13} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{13}}{2*2}=\frac{0+4\sqrt{13}}{4} =\frac{4\sqrt{13}}{4} =\sqrt{13} $
| 5v+8=-6+3v | | 9-x=-450 | | x^2+10x=-25. | | x^2=5x+36x2=5x+36 | | 14x-(3x-7)=95 | | m-8=18 | | 9n+5=5 | | 12g+8g=-12+11 | | 3(2x-3)-9=3x-27. | | 3x+20+2x=+x+40 | | 3x+20=+2x+x+40 | | (x+1)+5=3/2x+2 | | 3(2x+4)=18 | | 4^(2x+7)=〖32〗^x | | 3x+20)=(2x+40 | | (3x–7)+55+(x+20)=180 | | -6(3+3x)=-4-4x | | 5(x-2)=5x= | | 20-5(p+1)+3=-(2p-15) | | 2(x/3-1)=-6 | | 7m+3=8−6m | | 2x-7+8x+16=180 | | (1/3)x=243 | | 2(4x+x)=64 | | (x+8)(x+5)=x²+13x+40 | | $50=$5x10 | | 10+2n=4n-10 | | 4x-6=14= | | 8/5=12/n | | -7u-4=-8-6u | | (2x+5)(x-4)=20 | | 7m+3+8m=3-10m |