(2/5)+(5m/6)=(47/30)

Solution for (2/5)+(5m/6)=(47/30) equation:

(2/5)+(5m/6)=(47/30)

We move all terms to the left:

(2/5)+(5m/6)-((47/30))=0

We add all the numbers together, and all the variables

(+5m/6)+(+2/5)-((+47/30))=0

We get rid of parentheses

5m/6+2/5-((+47/30))=0

We calculate fractions


2250m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

2250m^2/()+2=0

We multiply all the terms by the denominator


2250m^2+2*()=0

We add all the numbers together, and all the variables

2250m^2=0

a = 2250; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2250·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{4500}=0$