(2/5)c+(4/5)c-6=c-7

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Solution for (2/5)c+(4/5)c-6=c-7 equation: 



(2/5)c+(4/5)c-6=c-7

We move all terms to the left:

(2/5)c+(4/5)c-6-(c-7)=0



Domain of the equation: 5)c!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

(+2/5)c+(+4/5)c-(c-7)-6=0

We multiply parentheses

2c^2+4c^2-(c-7)-6=0

We get rid of parentheses

2c^2+4c^2-c+7-6=0

We add all the numbers together, and all the variables

6c^2-1c+1=0

a = 6; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·6·1
Δ = -23
Delta is less than zero, so there is no solution for the equation

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