(2/5)c=13/5

Solution for (2/5)c=13/5 equation:

(2/5)c=13/5

We move all terms to the left:

(2/5)c-(13/5)=0


Domain of the equation: 5)c!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

(+2/5)c-(+13/5)=0

We multiply parentheses

2c^2-(+13/5)=0

We get rid of parentheses

2c^2-13/5=0

We multiply all the terms by the denominator


2c^2*5-13=0

Wy multiply elements

10c^2-13=0

a = 10; b = 0; c = -13;
Δ = b2-4ac
Δ = 02-4·10·(-13)
Δ = 520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{520}=\sqrt{4*130}=\sqrt{4}*\sqrt{130}=2\sqrt{130}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{130}}{2*10}=\frac{0-2\sqrt{130}}{20}
=-\frac{2\sqrt{130}}{20}
=-\frac{\sqrt{130}}{10}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{130}}{2*10}=\frac{0+2\sqrt{130}}{20}
=\frac{2\sqrt{130}}{20}
=\frac{\sqrt{130}}{10}
$