(2/5)h-7=(12/5)-2h+3

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Solution for (2/5)h-7=(12/5)-2h+3 equation: 



(2/5)h-7=(12/5)-2h+3

We move all terms to the left:

(2/5)h-7-((12/5)-2h+3)=0



Domain of the equation: 5)h!=0

h!=0/1

h!=0

h∈R





Domain of the equation: 5)-2h+3)!=0

h!=0/1

h!=0

h∈R



We add all the numbers together, and all the variables

(+2/5)h-((+12/5)-2h+3)-7=0

We multiply parentheses

2h^2-((+12/5)-2h+3)-7=0

We multiply all the terms by the denominator


2h^2*5)-2h+3)-((-7*5)-2h+3)+12=0

We add all the numbers together, and all the variables

2h^2*5)-2h+3)-((-35)-2h+3)+12=0

Wy multiply elements

10h^3-35)-2h+3)+12=0

We do not support ehpression: h^3

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