(2/5)h-7=(12/5)h-2h+3

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Solution for (2/5)h-7=(12/5)h-2h+3 equation: 


h in (-oo:+oo)

(2/5)*h-7 = (12/5)*h-(2*h)+3 // - (12/5)*h-(2*h)+3

(2/5)*h-((12/5)*h)+2*h-7-3 = 0

(2/5)*h+(-12/5)*h+2*h-7-3 = 0

-10 = 0

h belongs to the empty set

h belongs to the empty set

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