(2/5)h=-2-

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Solution for (2/5)h=-2- equation: 



(2/5)h=-2-

We move all terms to the left:

(2/5)h-(-2-)=0



Domain of the equation: 5)h!=0

h!=0/1

h!=0

h∈R



We add all the numbers together, and all the variables

(+2/5)h-0=0

We add all the numbers together, and all the variables

(+2/5)h=0

We multiply parentheses

2h^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{4}=0$

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